Solve by factoring. x² - 121 = 0 0 -11 11 11, -11 Solve by factoring. m² + 8m + 7 = 0 8,7 -7, 1 -7, -1 7, 1
Mathematics · High School · Tue Nov 03 2020
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Given the quadratic equation:
x^2 - 121 = 0
m^2 + 8m + 7 =0
Solve by factoring.
Solution:
For x^2 - 121 = 0, we transpose -121 on the other side of the equation, and take the square root of both sides in order to get the value of x, hence we must take note that when transposing a number, the sign changes.
x^2 - 121 = 0
x^2 = 121
x =± 11
For m^2 + 8m + 7, we will factor the values of m by thinking of a number that when added, the answer will be 8 and when multiplied the answer will be 7, hence the numbers that satisfy theses conditions are 1 and 7
( m + 1) (m + 7)
Solve for the value of m by equating each factor to 0.
m + 1 = 0
m = -1
m + 7 =0
m = -7
Final answer:
Factors of x^2 - 121 are: -11 and 11
Facotrs of m^2 + 8m + 7 are: -1 and -7