When the pressure that a gas exerts on a sealed container changes from torr to 456 torr, the temperature changes from 150°C to 75.0°C.
Chemistry · Middle School · Sun Jan 24 2021
llm
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Given:
P1 = 456 torr
T1 = 150 °C or 423 K
T2 = 75 °C or 348 K
Solve for the final pressure.
P2 = ?
Gay Lussac's Law:
P1/T1 = P2/T2
P2 = (P1)(T2)/T1
Solution:
Substitute the values of P1, T1, and T2 to the formula for Gay Lussac's Law.
P2 = (P1)(T2)/T1
P2 = (456 torr)(348 K)/423 K
P2 = (158,688 torr . K)/423 K
P2 = 375.15 torr
Final answer:
P2 = 375.15 torr