The ages of two brothers are in the ratio two to three, but in eight years, the ratio of their ages will be three to four. What is the age of the younger brother? 16 18 24
Mathematics · High School · Thu Feb 04 2021
Answered on
given that
let age of one brother =2x
let age of second brother=3x
ratio of ages = 2x/3x
in eight years age of first brother =2x+8
age of second brother= 3x+8 ratio of ages after 8 years =3/4
¾=(2x+8)/(3x+8)
cross multiplying :
4(2x+8) = 3( 3x+8)
8x +32 = 9x+ 24
x=8
age of older brother= 3x =3*8 =24 years
the age of one brother when he was younger is 2x =2*8 =16 years