integrate ∫dx/(64−x2) from 0 to 8.
Mathematics · High School · Wed Jan 13 2021
Answered on
Given:
∫dx (64−x^2)
Integrate from 0 to 8
Solution:
Before we can integrate from the intervals 0 to 8, we must first determine the anti derivative of the given. To do so, we apply the basic rules for constant which is to simply add the term, and for the terms, we add 1 to the exponent, then divide the number by the value of the exponent.
∫dx (64−x^2)
= 64x - x^3/3
= 64x - ⅓x^3 + C
Integrate from intervals 0 to 8.
= (64(8) - ⅓(8)^3) - 0
If we are asked to integrate from an interval of 0, the answer will be 0.
=512 - 170.6777
=341.3223
Final answer:
=341.3223