(3x^2−2x−1)(2x+4) Multiply
Mathematics · High School · Thu Feb 04 2021
Answered on
Given the equation:
(3x^2 - 2x - 1) (2x + 4)
Multiply.
Solution:
In order to solve the equation, we will use the FOIL Method, Multiply the first term of the first equation, to the first and last term of the second equation, and so on, until we'll came up with a product.
To clearly see how it works, here's a step by step solution.
= (3x^2)(2x)
=6x^3
First term of the first equation multiplied to the first term of the second equation.
=(3x^2)(4)
= 12x^2
First term of the first equation multiplied to the last term of the second equation.
=(-2x)(2x)
=-4x^2
2nd of the first equation multiplied to the first term of the second equation.
=(-2x)(4)
= -8x
2nd term of the first equation multiplied to the fast term of the second equation.
= (-1)(2x)
= -2x
Last term of the first equation multiplied to the first term of the second equation.
=(-1)(4)
= -4
Last term of the first equation multiplied to the fast term of the second equation.
=6x^3 + 12x^2 - 4x^2 -8x - 2x - 4
= 6x^3 + 8x^2 - 10x - 4
Final answer:
= 6x^3 + 8x^2 - 10x - 4