If the length is 3 more than 4 times the width of a rectangle and the perimeter is 76mm, what are the dimensions?
Mathematics · College · Thu Feb 04 2021
Answered on
Given that
x = the width
y = the length
P = 76 mm the perimeter
the length is 3 more than 4 times the width of a rectangle:
y = 3 + 4x
the perimeter is 76 mm and we know that the perimeter of rectangle is P = 2(width + length) that is P = 2(x + y)
2(x + y) = 76 divide both sides by 2
x + y = 38
by solving the system of equations:
y = 3 + 4x
x + y = 38
we find:
x = 7 mm
y = 31 mm
the dimensions of the rectangle are: the width is 7 mm and the length is 31 mm