For a free falling object weighing 3kg, what is the object's velocity 2 s after its release?
llm
Answered on
formula :
v =u+at
where:
v is the velocity at time t
u is the initial velocity
a=g=9.8 m/s^2 is the acceleration due to gravity
For the object in this problem, taking downward as positive direction, we have:
u=0 (the object starts from rest)
a=9.8 m/s^2
Therefore, the velocity after
t = 2 s
is:
v = 0+(9.8)(2)=19.6 m/s
v = 0+(9.8)(2)
=19.6m/s (downward)
Hence, object's velocity after its release is 19.6 m/s