Calculate the temperature of a gas that originally occupied 3.45 L and is expanded to 5.25 L. The original temperature of the gas was 282K and the pressure remains constant

To calculate the new temperature of the gas after it has expanded, you can use Charles's Law. Charles's Law states that for a given amount of gas at a constant pressure, the volume of the gas is directly proportional to its temperature in Kelvin. In mathematical terms, this is expressed as:

V1/T1 = V2/T2

where: V1 = initial volume T1 = initial temperature (in Kelvin) V2 = final volume T2 = final temperature (in Kelvin)

In your case, the original volume (V1) is 3.45 L, the original temperature (T1) is 282 K, and the final volume (V2) is 5.25 L. We need to solve for the final temperature (T2).

Let's rearrange the formula to solve for T2:

T2 = (V2 * T1) / V1

Now, plug in the given values:

T2 = (5.25 L * 282 K) / 3.45 L

Calculate T2:

T2 = (1474.5 L*K) / 3.45 L

T2 ≈ 427.25 K

The new temperature of the gas after expansion is approximately 427.25 K, assuming the pressure remains constant.