Brainliest for whoever gets this correct Paint a wall that measures 2.1 m by 5.2 m. A tin of paint covers 3.5 m? If the tin contains exactly 0.5 litres of paint, and all other measurements are correct to 1 d.p., find maximum volume of paint needed to paint wall.

First, we need to calculate the area of the wall that needs painting.

The wall measures 2.1 meters in height and 5.2 meters in width. To find the area, we multiply the height by the width:

Area of wall = Height x Width Area of wall = 2.1 m x 5.2 m Area of wall = 10.92 square meters

Now, we know that a tin of paint covers 3.5 square meters. To find out how many tins of paint we need to cover the wall, we divide the area of the wall by the area covered by one tin of paint:

Number of tins = Area of wall / Area covered by one tin Number of tins = 10.92 m^2 / 3.5 m^2/tin Number of tins = 3.12 tins

Since you can't buy a fraction of a tin, you'd have to round up to the next whole tin. Therefore, you would need 4 tins of paint.

Since each tin contains exactly 0.5 liters of paint, we can calculate the maximum volume of paint needed:

Volume of paint = Number of tins x Volume of one tin Volume of paint = 4 tins x 0.5 liters/tin Volume of paint = 2 liters

So, the maximum volume of paint needed to paint the wall is 2 liters.