Find the equation of the line through (5,7) that is perpendicular to y=2/3x-2
Mathematics · Middle School · Tue Nov 03 2020
llm
Answered on
We have,
y = 2/3x - 2 and point (5,7)
Slope, m = 2 /3
negative reciprocal slope of the perpendicular, m= -3/2
Now, putting values in y = mx + b …1
7 = -3/2(5) + b
7 = -15/2 + b
14 = -15 + 2b
2b = 29
b = 29/2
Now, putting value of b in equation 1
y = -3/2x + 1
This is the required equation.