a(t)=(t−k)(t−3)(t−6)(t+3) is a polynomial function of t, where k is a constant. Given that a(2)=0 , what is the absolute value of the product of the zeros of a?
Mathematics · High School · Tue Nov 03 2020
Answered on
Given the numerical equation:
a(t)=(t−k)(t−3)(t−6)(t+3)
Determinethe absolute value when a(2) =0
Substitute the value of t to the equation.
a(2) = ( 0 - k ) (0 - 3) ( 0 - 6) ( 0 + 3)
a(2) = (-k)(-3)(-6)(3)
a(2)= -54k
If we equate the value to 0, the answer will still be 0.
-54k= 0
k = 0
The constant is = 0, hence since the constant and function is equal to 0 the absolute value is equal to 0
Final answer:
The absolute value is equal to 0