A mixture containing initially 3.90 mole of NO(g) and 0.88 mole of CO2(g) was allowed to react in a flask of volume 1.00 L at a certain temperature according to the reaction CO2(g) + NO(g) ↔ CO(g) + NO2(g) At equilibrium 0.11 mole of CO2(g) was found present in the reaction mixture. Calculate the equilibrium constant Kc for the reaction at the temperature of the experiment.
Chemistry · High School · Tue Nov 03 2020
llm
Answered on
Answer:
Equilibrium constant Kc for the reaction will be 1.722
Explanation:
O2(g)+NO(g)→CO(g)+ NO2(g)
0.88 3.9 --- ---
0.88x 3.9-x x x
GIVEN:
0.88X-X= 0.11
⇒ X=0.77
CO2(g)+NO(g) → CO(g) + NO2(g)
0.88 3.9 --- ---
0.88-x 3.9-x x x
= 3.13 0.77 0.77
=0.11
Kc =
=
= 1.722