_____ 10. How many milligrams of active ingredient are required to prepare 10 mL of 0.3% (w/v) solution?
Mathematics · College · Tue Nov 03 2020
llm
Answered on
Given :
0.3% (w/v) solution, it can also be expressed as 0.3 g active ingredient for 100 ml of solution.
So,
0.3g/100ml × 1000mg/1g × 10ml = 30 mg
So, we need 30 mg of active ingredient to dilute in 10 ml of water.