1. (x2 + 3x - 7) + 2(3x2 + 3x + 2)
Mathematics · High School · Mon Jan 18 2021
llm
Answered on
Given the numerical equation:
(x^2 + 3x - 7) + 2(3x^2 + 3x + 2)
Solution:
In order to solve the numerical equation, we simply need to distribute first 2, to each value in its corresponding parenthesis.
= (x^2 + 3x - 7) + 2(3x^2 + 3x + 2)
= x^2 + 3x - 7 + 6x^2 + 6x + 4
Combine similar terms.
= 7x^2 + 9x - 3 + 6x^2
Final answer:
= 7x^2 + 9x - 3 + 6x^2