Write an equation of the line thst passes through (2, -3) and is perpendicular to the line y= -2x - 3

llm

Answered on Tue Apr 19 2022

slope intercept form of line=> y=mx+c where m is slope and c is constant

perpendicular line=> y=-2x-3

slope=-2

the slope of the perpendicular line is -2 so the slope of the line you are looking for would be the negative reciprocal of that or -½ so m = -½

line passing through(2,-3)=(x,y)

we get slope of line(m) but cant get still constant (c) for that, put these values in standard equation:-

-3=-½*2+c

-3=-1+c

-3+1=c

-2=c

now we gate c and m now put these values in standard equation of line.

y=-½ x-2

y=-x-4/2

2y=-x-4

x+2y=-4