Write a formula for quadratic function if its graph has the vertex at point (−2,5) and passes through the point (3,−10).
Mathematics · College · Thu Feb 04 2021
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the equation of vertex form :- y=a(x-k)^2+h
here, (k,h) are the points of vertex and (x,y) are the points that passing through the line
so (k,h)= (-2,5) and (x,y)=(3,-10)
put these values in the equation :- y=a(x-k)^2+h
-10=a(3-(-2))^2+5
-10=a(3+2)^2+5
-10=25a+5
-10-5=25a
-20=25a
a= -4/5
put this value in the equation:-
y=-4/5(x-(-2))^2+5
y=-4/5(x+2)^2+5 (Answer)