who to solve 6n+2f=736 and 10n+2f=920 by doing elimination

Mathematics · High School · Tue Nov 03 2020

Answered on

6n+2f=736        …1

10n+2f=920      …2

By using elimination method:

Subtracting equation 1 from 2, we get

6n + 2f -(10n+ 2f) = 736 - 920

6n + 2f -10n - 2f = -184

-4n = -184

n = -184/-4

n = 46

Now, putting value of n in equation 2, we get

10×46 + 2f = 920

460 + 2f = 920

2f = 920 - 460

2f = 460

f = 460/2

f = 230

 

Thus, value of n and f are 46 and 230 respectively.