who to solve 6n+2f=736 and 10n+2f=920 by doing elimination
Mathematics · High School · Tue Nov 03 2020
Answered on
6n+2f=736 …1
10n+2f=920 …2
By using elimination method:
Subtracting equation 1 from 2, we get
6n + 2f -(10n+ 2f) = 736 - 920
6n + 2f -10n - 2f = -184
-4n = -184
n = -184/-4
n = 46
Now, putting value of n in equation 2, we get
10×46 + 2f = 920
460 + 2f = 920
2f = 920 - 460
2f = 460
f = 460/2
f = 230
Thus, value of n and f are 46 and 230 respectively.