What would be the volume of a balloon containing 64g of oxygen gas at STP (standard temperature and pressure)? You should be able to obtain this answer by calculation or by using logical reasoning.

To calculate the volume of a balloon containing 64 g of oxygen gas at STP, you can use the molar volume of a gas at STP. At STP, which is defined as 0 degrees Celsius (273.15 K) and 1 atmospheric pressure (atm), one mole of any ideal gas occupies 22.4 liters.

First, determine how many moles of oxygen gas (O2) are present in the 64 g sample. Oxygen has a molar mass of approximately 16 g/mol, so the molecular weight of O2 (which is made up of two oxygen atoms) is 32 g/mol.

Now, calculate the number of moles of O2: Number of moles = mass of the gas / molar mass of the gas Number of moles of O2 = 64 g / 32 g/mol = 2 moles

Since at STP, one mole of any gas occupies 22.4 liters, two moles of O2 would occupy twice that volume: Volume at STP = number of moles × molar volume at STP Volume at STP = 2 moles × 22.4 L/mol = 44.8 liters

Therefore, the volume of the balloon containing 64g of oxygen gas at STP would be 44.8 liters.