What is the sum of 9+10 (;

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• To determine the solution set algebraically for the system of equations y = x^2 - 2x - 15 and y = 8x - 40, set the two expressions for y equal to each other: x^2 - 2x - 15 = 8x - 40. Now, solve for x by moving all terms to one side: x^2 - 2x - 8x + 15 + 40 = 0 x^2 - 10x + 55 = 0. The equation is now a quadratic equation. It can be solved either by factoring, completing the square, or using the quadratic formula. This equation does not factor easily, so we'll use the quadratic formula: x = [-(-10) ± √((-10)^2 - 4(1)(55))]/(2(1)) x = [10 ± √(100 - 220)]/2 x = [10 ± √(-120)]/2. Since we have a negative value under the square root, we have complex solutions. If we're considering only real solutions, we can conclude there are no real solutions for this system of equations. If complex solutions are allowed, then you would proceed with finding the two complex solutions. Please specify if you're interested in the complex solutions, and I will provide you with them.
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