what is the solution to this equation? 4x^2+98=0
Mathematics · High School · Thu Feb 04 2021
Answered on
Given the quadratic equation:
4x^2 + 98 = 0
Determine the solution.
Solution:
in order to determine the solution, we need to transpose 98 to the other side of the equation, hence we must take note that in transposing a number, the sign changes.
4x^2 + 98 = 0
4x^2 = - 98
Divide both sides of the equation by 4 in order to cancel out 4x^2 leaving behind x^2.
4x^2/4 = -98/4
x^2 = -24.5
Take the square root on both sides of the equation in order to cancel out x^2.
(x^2)^½ = (-24.5)^½
Since we have a negative number, this means that there will be no solution, since the result is a complex number.
x = No solution
Final answer:
No solution