What is the oxidation state of each individual carbon atom in c2o42−?
Chemistry · High School · Tue Nov 03 2020
llm
Answered on
We have,
C204 2−
Oxidation state of oxygen = -2
Now, we have to find out the oxidation state of carbon
So,
2x + 4(-2) = -2
2x - 8 = - 2
2x = -2 + 8
2x = 6
x = 6/2
x = + 3
Hence, oxidation state of carbon is + 3.