Use the parabola tool to graph the quadratic function. f(x)=2x2+4x−16 Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

To graph the quadratic function f(x) = 2x^2 + 4x - 16 using the parabola tool, we need to find the vertex and another point. A quadratic function in standard form is given by f(x) = ax^2 + bx + c.

Here is how to find the vertex: The x-coordinate of the vertex for a parabola in standard form is found by using the formula -b/(2a). In this case, a = 2 and b = 4. So, the x-coordinate is: x = -4/(2 * 2) = -4/4 = -1.

Next, we substitute x = -1 back into the function to find the y-coordinate of the vertex: f(x) = 2x^2 + 4x - 16 f(-1) = 2(-1)^2 + 4(-1) - 16 f(-1) = 2(1) - 4 - 16 f(-1) = 2 - 4 - 16 f(-1) = -18.

Therefore, the vertex of the parabola is (-1, -18).

To plot a second point, we can choose any x-value (different from the x-coordinate of the vertex). An easy choice is to use x = 0: f(0) = 2(0)^2 + 4(0) - 16 f(0) = -16.

This gives us the point (0, -16).

Now you have two points: 1. The vertex is at (-1, -18). 2. The second point is at (0, -16).

Finally, use your parabola tool to plot both points and draw the parabola. Since the coefficient of x^2 is positive, the parabola opens upwards, and these two points will help you draw its shape accurately.