Turn the equation into factored form Y=x^3+3x^3-6x-8
Mathematics · High School · Tue Nov 03 2020
llm
Answered on
We have, Y=x^3+3x^3-6x-8
By trial and error
let f(x)=x^3+3x^2−6x−8
let x=−1
so f(−1)= (-1)^3 + 3(-1)^2 -6(-1) -8
−1+3+6−8=0
so (x+1) is a factor
so,
x^3+3x^2−6x−8/x+1 = x^2+2x−8
Now, we have to factorise x^2+2x−8
x^2+2x−8 =0
x^2+4x- 2x−8 =0
x(x+4) -2(x+4) -0
(x−2)(x+4) = 0
Hence, factors of x^3+3x^2−6x−8 is (x+1)(x−2)(x+4)
x^3+3x^2−6x−8=(x+1)(x−2)(x+4)