The sum of 4 consecutive integers is 198
Mathematics · High School · Thu Feb 04 2021
llm
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Let the first integer be x
Then, next 3 integers be x+1, x+2, x + 3
According to question
x + x+1 + x+2 + x + 3 = 198
4x + 6 = 198
4x = 198-6
4x = 192
Dividing both sides by 4, we get
4x/4 = 192/4
x = 48
Thus, integer are 48, 49, 50, 51.