The perpendicular bisectors of ΔKLM intersect at point A. If AK = 25 and AM = 3n - 2, then what is the value of n?
Mathematics · College · Tue Nov 03 2020
llm
Answered on
The answer is n = 9.
Because the triangle is a perpendicular bisector and ΔKLM intersect at point A, AK and AM is equal.
To solve for the value of n and because AK=AM, You can write it out like this; 25= 3n - 2.
→ 25 = 3n - 2
→ 25+2 = 3n
→ 27 = 3n
→ 9 = n.