Th vertices of a sandbox are p(12, 14), Q(12, 17), R (16, 17) and S (16, 14).the coordinates are measured in feet . What is the perimeter of the sandbox ?

To find the perimeter of the sandbox, we will find the distance between the points using the distance formula and then add them together

p(12, 14), Q(12, 17), R (16, 17) and S (16, 14)

Distance formula:- 

D= root of (x2-x1)^2 + (y2-y1)^2

P= (12,14)=(x1,y1) , Q= (12,17)=(x2,y2)

PQ= root of (12-12)^2 + (17-14)^2

      =root of 0+(3)^2

      =root of 9

      =3

Q= (12,17)=(x1,y1) , R= (16,17)=(x2,y2)

QR= root of (16-12)^2 + (17-17)^2

      =root of (4)^2+0

      =root of 16

      =4

R= (16,17)=(x1,y1) , S= (16,14)=(x2,y2)

RS= root of (16-16)^2 + (14-17)^2

      =root of 0+(-3)^2

      =root of 9

      =3

P= (12,14)=(x1,y1) , S= (16,14)=(x2,y2)

PS= root of (16-12)^2 + (14-14)^2

      =root of (4)^2+0

      =root of 16

      =4

perimeter of the sandbox=PQ+QR+RS+PS

                                             =3+4+3+4

                                            =25 (Answer)