If the area of a rectangle is 8x^2+10x-3 and it’s width is 2x+3 what is the perimeter of this rectangle?
Mathematics · Middle School · Tue Nov 03 2020
llm
Answered on
Given :
Area of rectangle = 8x^2+10x-3
Width = 2x + 3
We know, Area of rectangle = Length × width
Length = 8x^2+10x-3/2x + 3
= 8x² + 12x - 2x - 3/2x +3
= 4x(2x +3) - 1(2x+ 3)/2x+3
= (4x-1)(2x+3)/(2x+3)
= 4x - 1
Perimeter = 2(Length + width)
= 2(4x - 1 + 2x + 3)
= 2(6x + 2)
= 12x + 4