Solve this linear system using determinants 2x + 3y = 6 - 8x - 3y = 12 A1 = 4= 4yl= DONE

Firstly right down the question properly

Here is the proper question to ask find  Solve this linear system using determinants 2x + 3y = 6,- 8x - 3y = 12 |A|=|Ax |=| Ay| |A|=|Ax |=| Ay| 

|A|=|Ax |=| Ay| |A|=|Ax |=| Ay| |A|=|Ax |=| Ay| 

Let's solve the question 

So the Linear system equation is 

2x + 3y = 6

- 8x - 3y = 12

So the coefficient matrix of the equation is A=[ 2     3

      -8     -3]

And  the answer column matrix is [6

                                                              12]We replace the x and y column in the coefficient matrix with the answers column matrix for getting Ax and Ay respectively

So Ax=[6   3

            12    -3] and Ay=[2   6

                                         -8    12].For finding determinants of A, Ax, and Ay

|A| =-6-(-24)=-6+24=18

|Ax|=-18-36=-54

|Ay|=24-(-48)=24+48=72

Note: for finding determinant of A  in a 22 matrix as given we multiple positions a11

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