PLZ HELP ITS 20 POINTS Using the linear combination method, what is the solution to the system of linear equations 5 x + 3 y = negative 10 and Negative 20 x minus 7 y = 15? (–5, 1) (–1, 5) (1, –5) (5, –1)
Mathematics · College · Thu Feb 04 2021
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We have to solve two equations with the linear combination method:
5x +3y = -10
=> 5x + 3y +10
-20x -7y = 15
=> 20x + 7y +15
We have two same variables in both equations, but their constants are different. We have to make a common pair for elimination
• So Firstly, multiple the first equation by -4 to make the x's constant the same:
= -4(5x + 3y +10)
= -20x -12y -10
• Add the equations, which result in eliminating x:
= -20x -12y -10 +20x +7y +15
= -5y +5
5y = 5
y = 5/5
y = 1
• Now put y=1 in equation two,
-20x -7y=15
-20x -7(1) =15
-20x -7 =15
-20x = 15 +7
-20x =22
-x = 22/20
-x = 1.1
x= -1.1
The values are x= -1.1; y= 1.