x2+4x+3=0 using quadratic formula
Mathematics · College · Mon Jan 18 2021
llm
Answered on
Formula :
x = [-b ± √(b² - 4ac)]/2a
We have,
x²+4x+3=0
Ax² + Bx + C = 0
Here,
A = 1
B = 4
C = 3
So, putting values in formula. We get,
x = [-4 ± √(4² - 4(1)(3))]/2× 1
x = [-4 ± √(16 - 12)]/2
x = [ -4 ± √4]/2
x = [-4±2]/2
Taking positive sign,
x = [-4 + 2]/2
x = -2/2
x = -1
Now, taking negative sign, we get
x = [-4 -2]/2
x = -6/2
x = -3
Hence, x = -1 and x = -3