Matt forgot to put the fabric softener in the wash. As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location? 3.8 E10 N/C 4.2 E10 N/C 2.4 E10 N/C 1.5 E10 N/C

To find the magnitude of the electric field (E) at the location of the charged piece of lint, we can use the relationship between electric force (F), charge (q), and electric field (E), which is given by the equation:

\[ F = qE \]

where F is the electric force (in newtons, N), q is the charge (in coulombs, C), and E is the electric field (in newtons per coulomb, N/C).

We can solve for E by rearranging the equation as follows:

\[ E = \frac{F}{q} \]

Given that the electric force (F) is 3.0 x 10^-9 N and the charge (q) is +1.25 x 10^-19 C, we can plug these values into the equation to find the electric field (E):

\[ E = \frac{3.0 \times 10^{-9} N}{1.25 \times 10^{-19} C} \]

\[ E = \frac{3.0}{1.25} \times \frac{10^{-9}}{10^{-19}} N/C \]

\[ E = 2.4 \times 10^{10} N/C \]

So, the magnitude of the electric field at this location is 2.4 x 10^10 N/C.