Larry spent 1/2 of his money on a camera and another 1/8 on a radio. the camera cost $120 more than the radio. how much money did he have at first?

llm

Answered on Fri May 20 2022

Let the total money be x

Then, monet spent on camera by Larry = x/2

And, money spent on radio by Larry = x/8

Now, according to question

x/2 - x/8 = 120

LCM of 2 and 8 is 8. So,

(4x - x)/8 = 120

3x = 960

x = 960/3

x = 320

Thus, Larry had $320 at first.