If now Kate is three times as old as Jan, and 6 years ago she was six times as old as he was, how old are they now? I will only accept the right answers.
Mathematics · College · Tue Nov 03 2020
Answered on
Let the present age of Kate be x
And, present age of Jan be t
Then, according to question
x = 3y ….1 [as Kate is 3 times old]
Kate's age 6 years ago = x -6
Jan's age 6 years ago = y -6
According to question
x- 6= 6(y-6) [as Kate is 6 times old]
x -6 = 6y - 36
x - 6y = -30 ….2
Putting value of x from equation 1 in equation 2, we get
3y - 6y = -30
-3y = -30
y = -30/-3
y = 10
Putting value of y in equation 1
x = 3(10)
x = 30
Hence, jan is 30 years old and Kate is 10 years old.