If f(x) = 4x^0 + (4x)^-1, what is the value of f(4)
Mathematics · Middle School · Tue Nov 03 2020
Answered on
To solve for the value of f(4), substitute the x in the f(x) = 4x^0 + (4x)^-1 into 4.
> f(x) = 4x^0 + (4x)^-1
> f(4) = 4(4)^0 + [4(4)]^-1
> f(4) = 16^0 + (16)^-1
Since 16 is raised to 0, the number becomes 0.
> f(4) = 0 + 16^-1
> f(4) = 16^-1
Because 16 is raised to -1, as a rule, move the numerator to the denominator and the denominator to the numerator.
> f(4) = 16^-1
> f(4) = 1/16
Therefore, the value of f(4) is 1/16,