If an athlete executing a long jump leaves the ground at a 30° angle and travels 7.80 m, what was the takeoff speed

Physics · High School · Tue Nov 03 2020

Answered on

Formula:

R = u²Sin2θ/g

Here, u = velocity

R = horizontal distance = 7.8 m

θ = 30° 

g = gravity = 10 m/s²

7.8 = u² Sin2×30°/10

7.8 ×10 = u² Sin60°

78 = u² × √3/2

78 × 2/1.73 = u²

u = 9.5 m/s