If an athlete executing a long jump leaves the ground at a 30° angle and travels 7.80 m, what was the takeoff speed
Physics · High School · Tue Nov 03 2020
llm
Answered on
Formula:
R = u²Sin2θ/g
Here, u = velocity
R = horizontal distance = 7.8 m
θ = 30°
g = gravity = 10 m/s²
7.8 = u² Sin2×30°/10
7.8 ×10 = u² Sin60°
78 = u² × √3/2
78 × 2/1.73 = u²
u = 9.5 m/s