How many moles of KCl will be produced from 89.0 g of KClO3?

To determine the number of moles of KCl produced from 89.0 g of KClO_3, we first need to know the balanced chemical equation for the reaction that generates KCl from KClO_3. A common reaction is the thermal decomposition of potassium chlorate (KClO_3) to form potassium chloride (KCl) and oxygen (O_2). This reaction is written as:

2 KClO_3 → 2 KCl + 3 O_2

From the balanced equation, we see that 2 moles of KClO_3 produce 2 moles of KCl. To find out how many moles of KCl will be produced from 89.0 g of KClO_3, follow these steps:

Step 1: Calculate the molar mass of KClO_3. The molar mass of KClO_3 is computed as follows: - Potassium (K): 39.10 g/mol - Chlorine (Cl): 35.45 g/mol - Oxygen (O): 16.00 g/mol (since there are three oxygen atoms, multiply by 3)

Molar mass of KClO_3 = (39.10 + 35.45 + (16.00 × 3)) g/mol Molar mass of KClO_3 = (39.10 + 35.45 + 48.00) g/mol Molar mass of KClO_3 = 122.55 g/mol

Step 2: Calculate the number of moles of KClO_3 in 89.0 g. Number of moles = mass (g) / molar mass (g/mol) Number of moles of KClO_3 = 89.0 g / 122.55 g/mol Number of moles of KClO_3 ≈ 0.726 moles

Step 3: According to the balanced equation, the molar ratio of KClO_3 to KCl is 1:1. Therefore, the number of moles of KCl produced will be the same as the number of moles of KClO_3 we started with. Number of moles of KCl = Number of moles of KClO_3 Number of moles of KCl ≈ 0.726 moles

So, from 89.0 g of KClO_3, you will produce approximately 0.726 moles of KCl.