How many atoms are present in 0.10mol of ptcl2 (nh3)2?

Chemistry · College · Thu Feb 04 2021

Answered on

To determine the number of atoms in a given amount of substance, you can use Avogadro's constant, which is approximately 6.022×1023 mol−1

6.022×1023

mol−1

. This constant represents the number of entities (atoms, molecules, ions, etc.) in one mole of a substance.

Given that you have 0.10 mol

0.10mol of PtCl2(NH3)2

PtCl2

​(NH3

​)2

​, you can use Avogadro's constant to find the number of molecules and then multiply by the number of atoms in one molecule.

Number of molecules= moles × Avogadro’s constant

Number of molecules=moles×Avogadro’s constant

Number of atoms=Number of molecules×Number of atoms per molecule

Number of atoms=Number of molecules×Number of atoms per molecule

The formula PtCl2(NH3)2

PtCl2

​(NH3​)2

​ indicates that there are 1 platinum (Pt) atom, 2 chlorine (Cl) atoms, and 4 nitrogen (N) atoms in each molecule.

So, for PtCl2(NH3)2

PtCl2

​(NH3​)2

​, there are 1+2+4=7

1+2+4=7 atoms in one molecule.

Now, plug in the values:

Number of molecules=0.10 mol×6.022×1023 mol−1

Number of molecules=0.10mol×6.022×1023

mol−1

Number of atoms=Number of molecules×7

Number of atoms=Number of molecules×7

Calculate these values to find the number of atoms in 0.10 mol

0.10mol of PtCl2(NH3)2

PtCl2

​(NH3​)2

​.