For A(1,3) and B(1,5) what is the equation of the perpendicular bisector of AB? y=[?]
Mathematics · Middle School · Mon Jan 18 2021
llm
Answered on
Given points are A(1, 3) and B(1,5).
Slope of AB = (y2 – y1)/(x2 – x1)
= (5 – 3)/(1 – 1)
= 2/0
= 0
Slope of perpendicular bisector of AB = 0
The perpendicular bisector passes through the midpoint of AB.
Midpoint of AB = (1+1)/2, (3+5)/2
= (1, 4)
Equation of perpendicular bisector is y – y1 = m(x – x1)
=> y – 4 = 0 (x – 1)
=> y-4=0 (equation of line)