Determine the magnitude of the acceleration experienced by an electron in an electric field of 531 N/C .
Physics · High School · Thu Feb 04 2021
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Electric field strength E=531 N/C
Mass of electron ==9.1×10-³¹kg
Charge on electron q=−1.6×10-²⁷ kg
Force on a charge particle inside an Electric field is
F = q* E
F=1.6 × 10-²⁷ × 531= 849.6 × 10-²⁷ N
acceleration (a) =F/m
a = 849.6× 10-²⁷/9.1×10−³¹
a=93.36 × 10⁴ m/s² (magnitude of the acceleration experienced by an electron in an electric field of 531 N/C ) .