A solid sphere of mass 0.6040 kg rolls without slipping along a horizontal surface with a translational speed of 5.080 m/s. It comes to an incline that makes an angle of 33.00° with the horizontal surface. To what vertical height above the horizontal surface does the sphere rise on the incline?
Physics · High School · Thu Feb 04 2021
llm
Answered on
v= 5.08 m/s
g = 9.81m/s²
change in kinetic energy = change in gravitational potential energy
= mv²/2 = mgh
Equate this in terms of h
h = v²/2g
h= (5.08)²/(2*9.81)
h =1.3153 m