Consider a population that is in Hardy–Weinberg equilibrium at a locus with two alleles, A and a, at frequencies of p and q, respectively. Assuming the population remains in Hardy–Weinberg equilibrium, what is the expected frequency of Aa heterozygotes after 100 generations? a. 1 b. 2pq c. 0.5 d. pq
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Answer B is correct - 2pq
Hardy–Weinberg Equilibrium (HWE) is a null model of the relationship between allele and genotype frequencies, both within and between generations, under assumptions of no mutation, no migration, no selection, random mating, and infinite population size.
The genotypic frequency in the model is calculated by
P² = genotype of a homozygous dominant trait
q² = genotype of a homozygous recessive trait
2pq = genotype of heterozygous trait.
Thus, P²+2pq+q²=1
In the given question, since the population is in equilibrium that is no evolutionary force is acting, therefore, the genotype frequency remains the same that is the frequency of Aa will remain same that is 2pq even after 100 generations.