Christian sold tickets to the game. Good seats were $5 each and poor seats cost $2 each. 210 people attended and paid $660. Write a system of linear equations that can be used to find how many good seats (g) and How many poor seats (p) were sold.

llm

Answered on Sun May 08 2022

Let g represent the # of good seats

and p the # of poor ones.

Then g + p = 210 seats.

Then p = 210 - g.

So:

($5)g + ($2)p = $660.

Substituting 210 - g for p

($5)g + ($2)(210 - g) = $660

Simplifying, 5g + 420 - 2g = 660 =>

3g = 240 =>

g = 80

Then there were 80 good seats and (210-80), or 130, poor seats.