An elevator descends into a mine shaft at the rate of 6 m/min. If the descend starts from 20 meter above the ground level, how long will it take to reach - 340m?
Mathematics · Middle School · Thu Feb 04 2021
Answered on
Considering the elevator to be at constant speed and the destination to be 350 m below ground level,
The elevator has to travel 20m till the ground, then 350 m more.
So, the total distance to travel is 370 m
If the elevator's speed is 6 metres/minute,
Then
Time= Distance/Speed
= 370/6
=61.67 minutes
=1 hour 2minute
Thus the elevator would take 1 hour 2 minute to reach its destination.