An 886 mL sample of Neon gas is at 752 torr and 299 K. What will be the new volume if, with the pressure and amount of gas held constant the temperature is decreased to 253 K?

Answer: To find the new volume of the Neon gas when the temperature is decreased while keeping the pressure and amount of gas constant, you can use Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature, as long as the pressure and the amount of gas remain constant. The formula for Charles's law can be written as:

V1 / T1 = V2 / T2

where - V1 is the initial volume of the gas - T1 is the initial temperature (in Kelvin) - V2 is the final volume of the gas - T2 is the final temperature (in Kelvin)

Let's rearrange the formula to solve for V2, the new volume:

V2 = (V1 * T2) / T1

Now plug the values into the formula:

V1 = 886 mL T1 = 299 K T2 = 253 K

V2 = (886 mL * 253 K) / 299 K V2 ≈ (224178 mL•K) / 299 K V2 ≈ 750.096 mL

Thus, the new volume of the Neon gas when the temperature is decreased to 253 K will be approximately 750 mL.