A motorcycle dealer paid a certain price for a motorcycle and marked it up by 1 l/4 of the price he paid. Later, he sold it for $16,000, What was the original price?

Related Questions

• The runner's speed increased steadily over the first two seconds of the race. The table shows the elapsed time and corresponding speed: Time (sec): 0 | 0.5 | 1 | 1.5 | 2 Speed (ft/sec): 0 | 5.1 | 9.3 | 12.5 | 15.6 To estimate the distance traveled during these two seconds, we use the speed at the end of each interval: Distance traveled = Sum of (Average speed of the interval * Time duration of the interval) From 0 to 0.5 seconds: Average speed = (0 + 5.1) / 2 = 2.55 ft/sec Distance = 2.55 ft/sec * 0.5 sec = 1.275 ft From 0.5 to 1 second: Average speed = (5.1 + 9.3) / 2 = 7.2 ft/sec Distance = 7.2 ft/sec * 0.5 sec = 3.6 ft From 1 to 1.5 seconds: Average speed = (9.3 + 12.5) / 2 = 10.9 ft/sec Distance = 10.9 ft/sec * 0.5 sec = 5.45 ft From 1.5 to 2 seconds: Average speed = (12.5 + 15.6) / 2 = 14.05 ft/sec Distance = 14.05 ft/sec * 0.5 sec = 7.025 ft Total distance traveled = 1.275 ft + 3.6 ft + 5.45 ft + 7.025 ft Total distance traveled = 17.35 ft None of the provided choices (A through E) matches the estimated distance of 17.35 ft calculated using the method provided. Please verify the choices or the estimation method.
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