4. Solve the simultaneous equations x+2y=3 2x+3y = 5
Mathematics · High School · Wed Jan 13 2021
llm
Answered on
We have,
x+2y=3 ….1
2x+3y = 5 ….2
Multiplying equation 1 by 2 and Subtracting equation 2 from 1, we get
2x + 4y - (2x + 3y) = 6 - 5
2x + 4y - 2x - 3y = 1
y = 1
Now, putting value of y in equation 1, we get
x + 2(1) = 3
x + 2 = 3
x = 3 -2
x = 1