What 3x+4 divided by 2x-3??
Mathematics · High School · Tue Nov 03 2020
Answered on
So lets try to write it mathematically:
(3x+4)/(2x-3)=
Lets try to multiply both sides with the denominators conjugate, so lets multiply it with (2x+3)
(3x+4)(2x+3)/(2x-3)(2x+3) =
We know that (a-b)(a+b) = a^2-b^2
In the dominators case we will have this:
(3x+4)(2x+3)/ (2x)^2 - 3^2
(3x+4)(2x+3)/4x^2 - 9
Lets multiply the brackets together.
6x^2+9x+8x+12/4x^2 - 9
6x^2+17x+12 / 4x^2 -9