16e^2-88e+121 pls help me
Mathematics · High School · Tue Nov 03 2020
Answered on
Given the quadratic equation:
16e^2 - 88e + 121
Solution
The given quadratic equation can be factored by using the quadratic formula.
The Quadratic formula:
x = −b ± √(b^2 − 4ac)/2a
is used to solve quadratic equations where a ≠ 0, in the form
ax^2+bx+c=0
a = 16, b = -88 c = 121
Substitute the given values of a, b, and c to the quadratic formula.
x = −(-88) ± √((-88)^2 − 4(16)(121))/2(16)
x = 88 ± √(7744 − 7744)/32
x = 88 ± √(0)/32
It must be taken to note that,
When b^2−4ac=0 there is one real root.
When b^2−4ac>0 there are two real roots.
When b^2−4ac<0 there are no real roots, only a complex number.
Since b^2 - 4ac = 0, there is only one real root.
x = 88/32
x = 2.75
Final answer:
x = 2.75 or 11 / 4