1) 3х + 8 y = 30 бx +7y = 6

Mathematics · Middle School · Wed Jan 13 2021

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We have,

3х + 8 y = 30         ….1

 бx +7y = 6            ….2

Using elimination method :

Multiplying equation 1 by 2, we get

6x + 16y = 60       …3

Subtracting equation 2 from 3, we get

6x + 16y - 6x - 7y = 60 - 6

9y = 54

y = 54/9

y = 6

Putting value of y in equation 1

3x + 8(6) = 30

3x + 48 = 30

3x = 30 - 48

3x = -18

x = -18/3

x = -6

 

Hence, value of x and y are -6 and 6 respectively.