write an equation in slope intercept form for the line with slope 1/5 and y-intercept -8 then graph the line
Mathematics · College · Thu Feb 04 2021
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equation of line => y-y1=m(x-x1) where (x1,y1) is y-intercepts
slope intercept form = y=mx+c where m is slope and c is constant
Given that:- slope of line = 1/5 and y- intercept is -8 and we can say that y- intercept is (0,-8)
put the values in the equation of line=>
y-(-8)=1/5(x-0)
y+8=1/5x
y=1/5x-8
hence, this is slope intercept form of the line where 1/5 is slope of line that is m and -8 is constant that is c.